The Aleksandrovsky District is an administrative-territorial unit of the Sakhalin department of the Russian Empire , which existed in 1884-1909 . Located on the island of Sakhalin . Center - Aleksandrovsk-Sakhalinsky.
| Alexandrovsky district | |
|---|---|
| A country |  Russian empire |
| Province | Sakhalin department |
| County town | Aleksandrovsk-Sakhalinsky |
| Population | 11,119 ( 1,897 ) people |
| Formed by | 1884 |
The Alexander District was formed as part of the Sakhalin department on May 15, 1884.
According to the census of 1897, 11,119 inhabitants lived in the district, of whom 5,249 were βfree statesβ, 2401 exiled students, 2,401 exiled settlers, 5,799 settlers from convicts 574 people.
The national composition in 1897 was as follows [1] : Russians - 60.2%, Nivkhs - 10.7%, Ukrainians - 7.3%, Poles - 5.9%, Tatars - 5.3%, Germans - 1, one %.
In 1898 there were 3 churches, 10 schools, 1 clinic and 3 okolotka in the district [2] .
In 1909, the Alexander District was transformed into the Alexander District.