Mariotte Vessel

The Mariotte siphon is a hermetically sealed vessel, into the cover of which a tube is opened that is open at both ends, immersed in liquid at one end and communicating with the other at the other.

Initially, when all the valves and the atmosphere-related opening in the tube are closed, the liquid level in the tube coincides with the liquid level in the vessel. If the vessel is not completely filled with liquid, there will be a certain amount of air above its surface, and pressure${\displaystyle \mathrm{<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">P</span></span>}}$ {\ displaystyle P \;}   at the bottom of the tube is calculated by the formula:

${\displaystyle \mathrm{<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">P</span></span>}<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">=</span></span>\mathrm{<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">\rho </span></span>}\mathrm{<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">g</span></span>}{\mathrm{<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">h</span></span>}}_{\mathrm{<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">0</span></span>}}<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">+</span></span>{\mathrm{<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">p</span></span>}}_{\mathrm{<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">0</span></span>}}}${\ displaystyle P = \ rho gh_ {0} + p_ {0}}   where:

• ${\displaystyle \mathrm{<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">\rho </span></span>}}${\ displaystyle \ rho}   - fluid density ;
• ${\displaystyle \mathrm{<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">g</span></span>}}${\ displaystyle g}   - acceleration of gravity ;
• ${\displaystyle {\mathrm{<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">h</span></span>}}_{\mathrm{<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">0</span></span>}}}${\ displaystyle h_ {0}}   - the distance between the surface of the liquid and the lower part of the tube;
• ${\displaystyle {\mathrm{<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">p</span></span>}}_{\mathrm{<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">0</span></span>}}}${\ displaystyle p_ {0}}   - pressure in space above water ( atmospheric pressure ).

If you open valve 3, then the tube, displacing the liquid in it, will fill the air, and the pressure above the surface will become equal${\displaystyle {\mathrm{<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">p</span></span>}}_{\mathrm{<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">0</span></span>}}<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">-</span></span>\mathrm{<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">\rho </span></span>}\mathrm{<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">g</span></span>}{\mathrm{<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">h</span></span>}}_{\mathrm{<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">0</span></span>}}}$ {\ displaystyle p_ {0} - \ rho gh_ {0}}   . At the end of the tube, atmospheric pressure${\displaystyle {\mathrm{<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">p</span></span>}}_{\mathrm{<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">0</span></span>}}}$ {\ displaystyle p_ {0}}   . The liquid from the hole will start to flow out only under the pressure of the liquid column between valves 2 and 3 (in the figure), which will remain constant all the time, while the end of the tube remains immersed in the liquid. Air will flow through the tube to the top of the vessel.

The fluid flow rate can be determined using the Torricelli formula ^[2] :

${\displaystyle \mathrm{<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">v</span></span>}<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">=</span></span>\sqrt{\mathrm{<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">2</span></span>}\mathrm{<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">g</span></span>}\mathrm{<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">h</span></span>}}}${\ displaystyle v = {\ sqrt {2gh}}}   where${\displaystyle \mathrm{<span\; class="mwe-math-element"><span\; class="mwe-math-mathml-inline\; mwe-math-mathml-a11y"\; style="display:\; none;">h</span></span>}}$ {\ displaystyle h}   - the distance between the lower end of the tube and the valve (or between valves 2 and 3 in the figure).

If, with the valve 3 open, open valve 2 located at the lower end of the tube, liquid will not flow out of it due to equal pressure on both sides of the valve. If valve 1 is opened with valve 3 open, liquid will also not flow out of it - instead, air will enter the vessel through valve 1, and pressure at the level of valve 3 and the flow rate of the jet will increase from it.

The main property of a Marriott vessel is that it allows you to adjust the fluid flow rate . This is used in continuous ink supply systems (CISS) ^[3] , for dosing liquids in laboratory conditions ^[4] , in fuel tanks for fuel oil burners of the evaporative type (in small boiler rooms).

• Hydrostatics
• Marriott, Edm
• Hydrostatic pressure