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Denjoy example

In the theory of dynamical systems , the example of Denjoy is an exampleCone {\ displaystyle C ^ {1}} C ^ 1 - a diffeomorphism of a circle with an irrational rotation number having a Cantor invariant set (and, accordingly, not conjugate to a pure rotation). M. Ehrman then constructed examples of such a diffeomorphism in the smoothness classCone+ε {\ displaystyle C ^ {1+ \ varepsilon}} {\ displaystyle C ^ {1+ \ varepsilon}} (i.e,Cone {\ displaystyle C ^ {1}} C ^ 1 with a Holder Derivative with exponentε {\ displaystyle \ varepsilon} \ varepsilon ) for anyoneε<one {\ displaystyle \ varepsilon <1} \ varepsilon <1 . This smoothness cannot be further increased: for diffeomorphisms with a Lipschitz derivative (and even with a derivative whose logarithm has limited variation), the Denjoy theorem holds that such a diffeomorphism with an irrational rotation number is conjugate to an irrational rotation (by the corresponding rotation number).

Content

  • 1 Design
    • 1.1 Example of homeomorphism
    • 1.2 Example in the classCone {\ displaystyle C ^ {1}} C ^ 1
    • 1.3 Class ExampleCone+ϵ {\ displaystyle C ^ {1+ \ epsilon}} {\ displaystyle C ^ {1+ \ epsilon}}
  • 2 See also
  • 3 References
  • 4 Literature

Design

 
Pasting procedure

Homeomorphism Example

The simplest example is a circle homeomorphism whose rotation number is irrational, but which, nevertheless, is not minimal . Namely, consider the rotationR {\ displaystyle R}   at some irrational angleα {\ displaystyle \ alpha}   , and choose an arbitrary starting pointx0 {\ displaystyle x_ {0}}   . Consider its orbitxn=Rn(x0) {\ displaystyle x_ {n} = R ^ {n} (x_ {0})}   (for all integersn {\ displaystyle n}   , both positive and negative). Let's make the following reorganization: at each pointxn {\ displaystyle x_ {n}}   cut the circle and paste the intervalIn {\ displaystyle I_ {n}}   some lengthln>0 {\ displaystyle l_ {n}> 0}   , so that the sum of the lengths of the glued intervals converges:

∑n=-∞∞ln<∞.{\ displaystyle \ sum _ {n = - \ infty} ^ {\ infty} l_ {n} <\ infty.}  

Then the set obtained after such gluing will still be a circle, moreover, it will have the natural Lebesgue measure (consisting of the Lebesgue measure on the cut old circle and the Lebesgue measure on glued intervals), that is, the length - and, thus, the smooth structure. Continuing the display arbitrarilyR {\ displaystyle R}   from the old circle so that it translates the intervalIn {\ displaystyle I_ {n}}   in the intervalIn+one {\ displaystyle I_ {n + 1}}   , - for example, choosing as an extension the affine mapping fromIn {\ displaystyle I_ {n}}   atIn+one {\ displaystyle I_ {n + 1}}   , - we get a homeomorphism f of a new circle with the same rotation numberα {\ displaystyle \ alpha}   . However, this homeomorphism has a Cantor invariant setK {\ displaystyle K}   (closure of the set of points of the old circle), and therefore it cannot be conjugated to irrational rotation.

Choosing a sequence of lengthsln {\ displaystyle l_ {n}}   so that the sequence of relationshipsln/ln+one {\ displaystyle l_ {n} / l_ {n + 1}}   remained limited atn→±∞ {\ displaystyle n \ to \ pm \ infty}   , for a construction with affine extension, we can achieve the Lipschitz property of the constructed homeomorphism. However, in order for the constructed map to be a diffeomorphism, the choice of extension to segmentsIn {\ displaystyle I_ {n}}   should be done more subtly.

Class exampleCone {\ displaystyle C ^ {1}}  

Class exampleCone {\ displaystyle C ^ {1}}   is constructed so that the derivative of the constructed diffeomorphismf {\ displaystyle f}   on the cantor setK {\ displaystyle K}   - closure of the set of points of the original circle - would be equal to 1 (since the Lebesgue measure on this set is preserved by the constructed diffeomorphism, this is a necessary condition for such a construction). Therefore, it is necessary to choose permuting intervalsIn {\ displaystyle I_ {n}}   limitationsφn=f|In:In→In+one {\ displaystyle \ varphi _ {n} = f | _ {I_ {n}}: I_ {n} \ to I_ {n + 1}}   so that the following conditions are met:

  • (D1) Derivativeφn {\ displaystyle \ varphi _ {n}}   at the ends of the intervalIn {\ displaystyle I_ {n}}   equal to 1.
  • (D2) Whenn→±∞ {\ displaystyle n \ to \ pm \ infty}   derivatives of mappingsφn {\ displaystyle \ varphi _ {n}}   evenly strive for 1.

The last condition is necessary, since with growthn {\ displaystyle n}   intervalsIn {\ displaystyle I_ {n}}   accumulate to the cantor setK {\ displaystyle K}   . Moreover, it is easy to see that these conditions are sufficient for the constructed mappingf {\ displaystyle f}   wouldCone {\ displaystyle C ^ {1}}   -diffeomorphism.

By the Lagrange theorem , on the intervalIn {\ displaystyle I_ {n}}   there is a point whose derivative is equal toln+one/ln {\ displaystyle l_ {n + 1} / l_ {n}}   . The second condition therefore requires that for the sequenceln {\ displaystyle l_ {n}}   took place

limn→±∞ln/ln+one=one.(∗){\ displaystyle \ lim _ {n \ to \ pm \ infty} l_ {n} / l_ {n + 1} = 1. \ qquad (*)}  

As it turns out, this condition on the lengths to buildCone {\ displaystyle C ^ {1}}   -diffeomorphism is also sufficient. Namely, the mappingsφn {\ displaystyle \ varphi _ {n}}   are selected as follows: on segmentsIn {\ displaystyle I_ {n}}   andIn+one {\ displaystyle I_ {n + 1}}   coordinates are entered that identify them with the segments[-ln/2,ln/2] {\ displaystyle [-l_ {n} / 2, l_ {n} / 2]}   and[-ln+one/2,ln+one/2] {\ displaystyle [-l_ {n + 1} / 2, l_ {n + 1} / 2]}   respectively, and mappingφn {\ displaystyle \ varphi _ {n}}   selected as

φn=Fln+one-one∘Fln,(∗∗){\ displaystyle \ varphi _ {n} = F_ {l_ {n + 1}} ^ {- 1} \ circ F_ {l_ {n}}, \ qquad (**)}  

Where

Fl:[-l/2,l/2]→R,Fl(x) = l tan ⁡ π x l . ( ∗ ∗ ∗ ){\ displaystyle F_ {l}: [- l / 2, l / 2] \ to \ mathbb {R}, \ quad F_ {l} (x) = l \ tan {\ frac {\ pi x} {l} }. \ qquad (***)}  

A simple computation then shows that the derivativeφn {\ displaystyle \ varphi _ {n}}   at any point deviates from 1 in no more thanconst⋅|one-lnln+one| {\ displaystyle \ mathrm {const} \ cdot | 1 - {\ frac {l_ {n}} {l_ {n + 1}}} |}   , therefore, condition (*) is sufficient to satisfy the second necessary condition D2. On the other hand, it is equally easy to see that condition D1 is also fulfilled (it is for this that the tangent in the formula (***) and multiplied by l: then the speed of departure to infinity at the endsone/x {\ displaystyle 1 / x}   , and does not depend on the length of the interval l - therefore, the composition quotient concerns the identity map).

Selection of any satisfying (*) sequenceln {\ displaystyle l_ {n}}   with a convergent amount - for example,ln=one/(one+n2), {\ displaystyle l_ {n} = 1 / (1 + n ^ {2}),}   - and completes the construction.

Class exampleCone+ϵ {\ displaystyle C ^ {1+ \ epsilon}}  

Class exampleCone+ε {\ displaystyle C ^ {1+ \ varepsilon}}   presented by the construction already described above, but with more subtle conditions for lengthsln {\ displaystyle l_ {n}}   . Namely, as it is easy to see, the constructed diffeomorphism will have a Hölder derivative if and only if the derivatives of all restrictionsφn {\ displaystyle \ varphi _ {n}}   uniformly acrossn {\ displaystyle n}   Hölder. Indeed, comparing derivatives at points from different segments, we can subdivide this difference by derivatives at intermediate end points (since the derivative at the end point is always equal to 1) and use the triangle inequality (in the worst case, double the Hölder constant).

Since on the segmentIn {\ displaystyle I_ {n}}   there is a point with a derivativeln+one/ln {\ displaystyle l_ {n + 1} / l_ {n}}   (by the Lagrange theorem) there is a point whose derivative is equal to 1 (this is the end point), the Hölder constant for the Hölder exponentε {\ displaystyle \ varepsilon}   cannot be less than

(|one-ln+oneln)/lnε=|ln+one-ln|lnone+ε.(L){\ displaystyle (| 1 - {\ frac {l_ {n + 1}} {l_ {n}}}) / l_ {n} ^ {\ varepsilon} = {\ frac {| l_ {n + 1} -l_ {n} |} {l_ {n} ^ {1+ \ varepsilon}}}. \ qquad (L)}  

Therefore, the expression (L) should be limited whenn→±∞ {\ displaystyle n \ to \ pm \ infty}   . It turns out that this condition of boundedness is sufficient - an explicit calculation shows that the exact Hölder constant of the constraintφn {\ displaystyle \ varphi _ {n}}   differs from the lower bound (L) no more than a constant time. To complete the construction, it remains to present a two-sided infinite sequenceln {\ displaystyle l_ {n}}   with a convergent sum for which expression (L) remains bounded. An example of such a sequence is

ln=onemln2⁡m,m=2+|n|,{\ displaystyle l_ {n} = {\ frac {1} {m \ ln ^ {2} m}}, \ quad m = 2 + | n |,}  

suitable for everyone at the same timeε<one {\ displaystyle \ varepsilon <1}   .

The presentation of such a sequence completes the construction - the constructed diffeomorphism belongs to the classCone+ε {\ displaystyle C ^ {1+ \ varepsilon}}   with anyε<one {\ displaystyle \ varepsilon <1}   .

See also

  • Denjoy theorem
  • Poincare’s theorem on the classification of circle homeomorphisms

Links

  • Notes by J. Milnor Introductory Dynamics Lectures , lecture "Denjoy Theorem" (see §15B).

Literature

  • A.B.Katok, B. Hasselblat. Introduction to the theory of dynamical systems with a review of recent achievements / Transl. from English under the editorship of A.S. Gorodetsky. M.: МЦНМО, 2005. ISBN 5-94057-063-1
  • M.Herman, Sur la conjugaison différentiable des difféomorphismes du cercle à des rotations. Publications Mathématiques de l'IHÉS, 49 (1979), p. 5-233.
Source - https://ru.wikipedia.org/w/index.php?title=Example_Danjois&oldid=24836831


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Clever Geek | 2019